A Box Contain 100 Tickets Numbered 1, 2,…100. Two Tickets Are Chosen At Random. It Is Given That The Greater Number On The Two Chosen Tickets Is Not More Than 10. The Probability That The Smaller Number Is 5 Is:

The chance of an event happening is the square of the chance of happening of second event but the odds against the first are the cube of the odds against the second. The chance of the events:

The odd against a certain event are 5: 2 and the odds in favour of another independent event are 6: 5 the probability that at least one of the events will happen is:

If A₁, A₂,….A_n are any n events, then

The probability that at least one of the event A and B occurs is 0.6 if A and B occur simultaneously with probability 0.2, then 

Odds in favour of an event A is 2 to 1 and odds in favour of A∪ B are 3 to 1. Consistent with information the smallest and largest values for the probability of event B are given by:

An integer is chosen at random from the first 200 positive integers. The probability that the integer chosen is divisible by 6 or 8 is:

If ten objects are distributed at random among ten persons, the probability that at least one of them will not get object is:

If two events A and B are such that 

One ticket is selected at random from 100 tickets numbered 00, 01, 02,…99. Suppose A and B are the sum and product of the digits found on the ticket. Then P(A = 7/8 = 0) is given by:

A bag contains four tickets marked with numbers 112, 121, 211, 222. One ticket is drawn at random from the bag. Let

E_i(i = 1, 2, 3) denote the event that its digit on the ticket is 2. Than: