Five Coins Whose Faces Are Marked 2, 3 Are Thrown. The Probability Of Obtaining A Total Of 12 Is:

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Question

easy

Correct option is

5/16

The only way sum can be 12 is when we get 3 on two thrown and 2 on three throw, i.e. 2 2 2 3 3 and its permutations

Let occurrence of 2 be success and 3 be failure

To get 2 2 2 3 3 , we want 3 success and 2 failures