## Question

The fundamental frequency of a longitudinal vibrating of a rod clamped at its centre is 1500 Hz. If the mass of the rod is 96 g the increase in its total length produced by a stretching force of 10 kg weight will be:

### Solution

0.011 cm

The wavelength of waves in the rod = 2*l* (*l* = length of rod).

Since the vibrations are longitudinal,

Since *V* = *Al* (where *A* is the area of c.s.)

If *x* is the increase in length produced by 10 kg weight, it follows:

from eq. (2) and (3),

Solving, we get *x* = **0.011 cm**.

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