The Ist IEs Of Four Consecutive Elements Present In The Second Period Of Periodic Table Are 8.3, 11.3, 14.5 And 13.6 EV Respectively. Which Of These Is The IE Of Nitrogen?   

Why Kaysons ?

Video lectures

Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation.

Online Support

Practice over 30000+ questions starting from basic level to JEE advance level.

Live Doubt Clearing Session

Ask your doubts live everyday Join our live doubt clearing session conducted by our experts.

National Mock Tests

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

Organized Learning

Proper planning to complete syllabus is the key to get a decent rank in JEE.

Test Series/Daily assignments

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

SPEAK TO COUNSELLOR ? CLICK HERE

Question

The Ist IEs of four consecutive elements present in the second period of Periodic Table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which of these is the IE of nitrogen?   

Solution

Correct option is

14.5

Generally in a period, IE increases but nitrogen due to the presence of half-filled p-subshell (stable configuration) has higher IE as compared to its consecutive elements. Thus, the IE of nitrogen is 14.5. 

SIMILAR QUESTIONS

Q1

The correct order of ionic radius is

Q2

The bond length or LiF will be

Q3

The ionic radius of ‘Cr’ is minimum in which of the following compounds?

Q4

The incorrect statement among the following is

Q5

Which ionisation potential (IP) in the following equations involves the greater amount of energy?

Q6

The first four ionisation energy values of an element are 191, 578, 872 and 5962 kcal. The number of valence electrons in the element is

Q7

Which one of the following elements has the highest ionisation energy?

Q8

In the Periodic Table, going down in the fluorine group

Q9

Which of the following transition involves maximum amount of energy?

Q10

 

The formation of the oxide ion O2–(g) requires first an exothermic and then an endothermic step as shown below  

               

                    

This is because