Question

How many years would it take to spend Avogadro’s number of rupees at the rate of 10 lakh rupees per second?

Solution

Correct option is

1.9089×1010 years

 

                  = 

                = 1.9089×1010 years

SIMILAR QUESTIONS

Q1

0.1 mole of a carbohydrate with empirical formula CH2O contains 1 g of hydrogen. What is its molecular formula? 

Q2

The percentage of an element M is 53 in its oxide of molecular formula M2O3. Its atomic mass is about

Q3

80 g of oxygen contain as many atoms as in 

Q4

A black dot used as a full stop at the end of a sentence has a mass of about one attogram. Assuming that the dot is made up of carbon, calculate the approximate number of carbon atoms presents in the dot?  

Q5

Insulin contains 3.4% sulphur. Calculate the minimum molecular mass of insulin.

Q6

 atoms of iron weigh as much as 1cc of H2 at S.T.P. What is the atomic mass of iron?

Q7

4 g carbon were heated with 8 g of sulphur. How much carbon disulphide (CS2) will be formed when the reaction is completed? What will be its percentage purity?  

Q8

Gastric juice contains about 3.0 g of HCl per litre. If a person produces about 2.5litre of gastric juice per day, how many antacid tablets each  containing 400 mg of Al(OH)­3 are needed to neutralize all the HCl produced in one day. 

Q9

What volume at N.T.P of ammonia gas will be required to be passed into 30mL of N H2SO4 solution to bring down the acid normality to 0.2 N?

Q10

The vapour density of a mixture of NO2 and N2O4 is 38.3 at 26.7oC. Calculate the number of moles of NO2 in 100 g of the mixture.