Question

Solution

Correct option is

0.437

Suppose NO2 present in 100 g of the mixture = g

Then N2O4 present in the mixture = (100 – x)g

Molar mass of NO2 = 14 + 32 = 46 g mol–1

Molar mass of N2O4 = 92 g mol–1

Molar mass of mixture Expressing all quantities in terms of moles, we should have or  92 + 4600 – 46= 5524.8

or 46x = 924.8

or     x = 20.1 g SIMILAR QUESTIONS

Q1

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Q2

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Q3 atoms of iron weigh as much as 1cc of H2 at S.T.P. What is the atomic mass of iron?

Q4

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Q5

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Q6

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Q7

What volume at N.T.P of ammonia gas will be required to be passed into 30mL of N H2SO4 solution to bring down the acid normality to 0.2 N?

Q8

The mass of one litre sample of ozonised oxygen at N.T.P was found to be 1.5 g. when 100mL of this mixture at N.T.P were treated with turpentine oil, the volume was reduced to 90mL

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Q9

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Q10

How many molecules are there in 10 litres of gas at a pressure of 75 cm at 27 degree Celsius?