## Question

### Solution

Correct option is

0.0802 mol

In KBr, 32.9 g of K are combined with 67.1 g of Br

Thus Br2 is the limiting reactant.

K reacted = 3.14 g

= 0.0802 mol

#### SIMILAR QUESTIONS

Q1

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Q2

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Q3

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Q4

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Q5

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Q6

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Q7

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Q8

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Q9

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Q10

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