Potassium bromide, KBr contains 32.9% by mass of potassium. If 6.40 g of bromine reacts with 3.60 g of potassium, calculate the number of moles of potassium which combine with bromine to from KBr.
In KBr, 32.9 g of K are combined with 67.1 g of Br
Thus Br2 is the limiting reactant.
K reacted = 3.14 g
= 0.0802 mol
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