## Question

### Solution

Correct option is    After removing 1021 molecules, molecules left

= (2.738 – 1) 1021

=  #### SIMILAR QUESTIONS

Q1

10 mL of HCl solution gave 0.1435 g of AgCl when treated with excess of AgNO3. Find the normality of the acid solution Q2

A sample of hard water contains 20 mg of Ca2+ ions per litre. How manymilliequivalents of Na2CO3 would be required to soften 1 litre of the sample?

Q3

A plant virus is found to consist of uniform cylindrical particles of 150 Å in diameter and 5000 Å long. The specific volume of the virus is 0.75 cm3/ g. If the virus is considered to be a sample particle, find its molecular weight.

Q4

The formula weight of an acid is 82.0 in a titration 100 cm3 of a solution of this acid containing 39.0 g of the acid per litre were completelyneutralised by 95.0 cm3 of aqueous NaOH containing 40 .0 g of NaOHper litre. What is the basicity of the acid?

Q5

An analysis of a pyrex glass showed 12.9% B2O3, 2.2% Al2O3, 3.8% Na2O, 0.4% K2O and remaining is SiO2. What is the ratio of Si to B atoms in the glass?

Q6

One litre of a gas is at a pressure of 10–6 mm of Hg at 25oC. How many molecules are present in the vessel?

Q7

27 g of Al (at mass = 27) will react with oxygen equal to

Q8

2.76 g of silver carbonate (at mass of Ag = 108) on being heated strongly yields a residue weighing

Q9

If 0.5 mol of BaCl2 is mixed with 0.2 mol of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is

Q10

The  number of gram molecules of oxygen in molecules is