The Percentage Of Se In peroxidase anhydrous Enzyme Is 0.5% By Weight (atomic Weight = 78.4). Then Minimum Molecular Weight Of peroxidaseanhydrous Enzyme Is

Why Kaysons ?

Video lectures

Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation.

Online Support

Practice over 30000+ questions starting from basic level to JEE advance level.

Live Doubt Clearing Session

Ask your doubts live everyday Join our live doubt clearing session conducted by our experts.

National Mock Tests

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

Organized Learning

Proper planning to complete syllabus is the key to get a decent rank in JEE.

Test Series/Daily assignments

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.



The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic weight = 78.4). Then minimum molecular weight of peroxidaseanhydrous enzyme is


Correct option is


0.5%  by weight means 0.5 g Se is present in 100 g of peroxidaseanhydrous enzyme. As at least one atom of Se must be present in the enzyme and atomic weight of Se = 78.4, therefore 1 g atom of Se, i.e.,78.4 g will be present in enzyme




Haemoglobin contains 0.33% of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (at wt. of Fe = 56) present in one molecule of haemoglobin is 


In the reaction, 4 NH3 (g) + 5 O2 (g) → 4 NO (g) + H2O (l), when 1 mole of ammonia and 1 mole of O2 are made to react to completion 


50mL 10 N H2SO4, 25mL 12 N HCl and 40 mL 5 N HNO3 were mixed together and the volume of the mixture was made 1000mL by adding water. The normality of the resultant solution will be : 


The number of atoms in 4.25 g of NH3 is approximately


A 100mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30mL of NaOH solution. The remaining titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is 


One mole of calcium phosphide on reaction with excess of water gives


Number of g of oxygen in 32.2 g Na2SO4. 10H2O is


 The percentage of nitrogen in urea is about


How much of NaOH is required to neutralize 1500 cm3 of 0.1 N HCl? (Na = 23)


10 dm3 of N2 gas and 10 dm3 of gas X at the same temperature contain the same number of molecules. The gas X is