Question

Solution

Correct option is

56 g

2 KOH       +     CO2    →  K2CO3  +   H2O

2(39+16+1)        22.4 L

= 112 g         at STP

22.4 dm3 of CO2 at STP require KOH = 112g

11.2 dm3 of CO2 at STP will require KOH

= 56 g

SIMILAR QUESTIONS

Q1

116 mg of a compound on vaporisation in a victor Meyer’s apparatus displace 44.8 mL of air measured at STP. The molecular weight of the compound is

Q2

100 g CaCO3 is treated with 1 litre of 1 N HCl. What would be the weight of CO2 liberated after the completion of the reaction?

Q3

If we consider that , in place of , mass of carbon atom is taken to be relative atomic mass unit, the mass of one mole of a substance will

Q4

For the formation of 3.65 g of hydrogen chloride gas, what volumes of hydrogen gas and chlorine gas are required at N.T.P. conditions?

Q5

An alkaloid contains 17.28% of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in one molecule of the alkaloid is

Q6

If 30mL H2 and 20mL of O2 react to form water, what is left at the end of the reaction?

Q7

How many moles of magnesium phosphate, Mg3(PO4)2 will contain 0.25 mole of oxygen atoms?

Q8

1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of the metal is

Q9

The number of g-atom of oxygen in CO molecules is

Q10

500 mL of NH3 contain molecules at S.T.P. How many molecules are present in 100 mL of CO2 at S.T.P.?