## Question

### Solution

Correct option is

108 g of Ag (108)

Number of atoms = number of moles × Avogadro’s number (NA Number of atoms in 56 g of Fe Number of atoms in 27 g of Al = 27/27 NA = NA

Number of atoms in 108 g of Ag = 108/108 NA = NA.

Hence, 24 g of carbon has the maximum number of atoms.

#### SIMILAR QUESTIONS

Q1

Pressure is determined as force per unit area of the surface. The S.I unit of pressure, pascal, is as shown below:

1Pa = 1 Nm–2

If mass of air at sea level is 1034g cm-2, calculate the pressure in pascal.

Q2

Determine the molecular formula of an oxide of iron in which the mass percent of iron and oxygen are 69.9 and 30.1 respectively. Given that the molar mass of the oxide is (Atomic mass: Fe = 55.85, O = 16.00 amu)

Q3

A gaseous mixture contains oxygen and nitrogen in the ratio of 1:4 by weight. Therefore, the ratio of their number of molecules is

Q4

The total number of electrons in one molecule of carbon dioxide is

Q5

The largest number of molecules is in

Q6

When the same amount of zinc is treated separately with excess ofsulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is

Q7

2.76 g of silver carbonate on being strongly heated yields a residue weighing

Q8

If 0.50 mole of BaCl2 is mixed with 0.20 mole of Na3PO4, the maximum number of moles of Ba(PO4)2 that can be formed is

Q9

How many moles of electron weighs one kilogram?