Question

In nitroprusside ion, the iron and NO exists as Fe(II) and rather than Fe(III) and NO. This can be established by

Solution

Correct option is

Measuring the solid state magnetic moment

 

Fe(II) state – 3d6 ; due to strong CN ligand spin paired complex (d2sp3) will be formed. 

Hence n = 0, μ = 0 B.M   

Fe(III) state 3d5;d2sp3 complex, n = 1, μ = 1.73 B.M.

SIMILAR QUESTIONS

Q1

When HgI2 is added to excess of aqueous KI, mercury largely exists as

Q2

The solution of AgBr in presence of large excess of NH3 contains mainly the cation

Q3

 

The molar ionic conductances of the octahedral complexes :

(i) PtCl4.5NH3                       (ii) PtCl4.4NH3

(iii) PtCl4.3NH3                     (iv) PtCl4.2NH3

Follow the order

Q4

On treatment of 100 ml of 0.1 M solution of the complex CrCl3.6H2O with excess of AgNO3.4.305g of AgCl was obtained. The complex is

Q5

Which of the following species is not expected to be a ligand

Q6

 

EAN of the central metal in the complexes :

      K2[Ni(CN4].[Cu(NH34]SO4 and K2[PtCl6]

are respectively

Q7

Which of the following pair of complexes have the same EAN of the central metal atoms/ions?

Q8

The complexes that violates the Sidwicks’s rule of EAN is

Q9

The complex ion which has no ‘d’ electrons in the central metal atoms is

Q10

Oxidation number of Fe in violet coloured complex Na4[Fe(CN)5(NO)S] is