Question

On treatment of [Ni(NH3)4]2+ with concentrated HCl, two compounds I and II having the same formula, Ni(NH3)2Cl2 are obtained. I can be converted into II by boiling with dilute HCl. A solution of I reacts with oxalic acid to form [Ni(NH3)2(C2O4) whereas II does not react. Point out the correct statement of the following

Solution

Correct option is

I cis, II trans; both square planar

Only cis isomer can easily form a chelate ring with oxalate group; the trans isomer cannot form a chelate ring. Both are square planar.

SIMILAR QUESTIONS

Q1

Octahedral complex of Cr(III) will be

Q2

For the correct assignment of electronic configuration of a complex, the valence bond theory often requires the measurement of

Q3

Mn2+ forms a complex with Br ion. The magnetic moment of the complex is 5.92 B.M. What would be the probable formula and geometry of the complex? 

Q4

How many isomers are possible for the complex ion [Cr(NH3)(OH)2Cl3]2–

Q5

A complex of certain metal has the magnetic moment of 4.91 BM whereas another complex of the same metal with same oxidation state has zero magnetic moment. The metal ion could be

Q6

The EAN of metal atoms in Fe(NO)2(CO)2 and Co2(CO)8 respectively are

Q7

The value of in HxCr(CO)5 is

Q8

Following Sidwick’s rule of EAN, Co2(CO)x will be

Q9

 

In the reactions  

   

two isomers of the product are obtained. The initial complex is

Q10

The aqueous 0.01 m of [Co(NH3/6][Co(NH3)(NO2)5]3 is expected to have the depression of freezing point (Kf for water = 1.86 K/m)