Question

The dipole moments of the given molecules are such that:

Solution

Correct option is

NH3 > NF3 > BF3

 

NH3 > NF3 > BF3   

This is due to different directions of the bond moments of N – H and N – F bonds. In NH3, N is more electronegative but in NF3, F is more electronegative. Thus in NH3, the dipole-moment of N – F bond are in the same direction as that of the love pair. BF3 being trigonal planer has zerodipole moment.   

SIMILAR QUESTIONS

Q1

The oxide of chlorine is a colourless oily liquid and most acidic:

Q2

XeOF4 is prepared by:

Q3

When dry chlorine is passed through silver chlorate heated to 90oC, then which of the oxide of chlorine is obtained?

Q4

Cl2O6 dissolves in sodium hydroxide to form:

Q5

 

When any chloride is heated with conc. H2SO4, then HCl is obtained while when any bromide is heated with conc. H2SO4, then Br2 is obtained and not HBr.

This is because

Q6

When PH3 is passed through copper sulphate solution, then copper phosphide is obtained. This is because:

Q7

When oxalic acid is heated with concentrated H2SO4 it gives:

Q8

Acid strength of oxoacids of chlorine is in order: 

Q9

 

NH4ClO4 + HNO(dil.) âŸ¶ HClO4 + [X]           

Q10

Nitrogen dioxide cannot be obtained by heating: