## Question

### Solution

Correct option is

6.02 × 1018 mol–1

Due to addition of SrCl2, each Sr2+ ion replace to Na+ ions, but occupies only one Na+ lattice point. This makes one cationic vacancy.

Number of moles of cation vacancies in 100 mol of  NaCI = 10-3

Number of moles of cation vacancies in 1 mol =

Total cationic vacancies = 10-5 × NA

= 10-5 × 6.023 × 1023

= 6.023 × 1018 mol-1

#### SIMILAR QUESTIONS

Q1

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Q2

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Q4

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Q5

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Q6

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Q7

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Q8

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Q9

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Q10

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