## Question

### Solution

Correct option is

15.05%

From the valency of Fe (II) and Fe (III), it is clear that three Fe (II) ions will be replaced by two Fe (III) causing a loss of one iron ion. Total loss of iron from one molecule of FeO = 1 – 0.93 = 0.07

Hence, total Fe(III) present in one molecule of

FeO = 2 × 0.07 = 0.14

Total number of Fe (II) and Fe (III) present in one molecule of

FeO = 0.93

Hence, percentage of Fe (III) = #### SIMILAR QUESTIONS

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