The Ratio Of Close Packed Atoms To Tetrahedral Holes In Cubic Close Packing Is

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Question

The ratio of close packed atoms to tetrahedral holes in cubic close packing is

Solution

Correct option is

1:2

 

Every constituent has two tetrahedral voids. In ccp lattice

atom =      

 ∴ tetrahedral voids = 4 × 2 = 8

Thus, ratio = 4: 8 = 1: 2

SIMILAR QUESTIONS

Q1

Under which category iodine crystals are placed among the following?

Q2

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Q3

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Q4

An example of a substance possessing giant covalent structure is

Q5

The edge of unit cell of fcc Xe crystal is 620 pm. The radius of Xe atom is

Q6

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Q7

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Q8

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Q9

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Q10

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