When A Certain Crystal Was Studied By The Bragg Technique Using X – Rays Of Wavelength 229 Pm, An X – Ray Reflection Was Observed At An Angle Of 230 20’. What Is The Corresponding Interplanar Spacing? [sin (23020’) = 0.396]

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Question

When a certain crystal was studied by the Bragg technique using X – rays of wavelength 229 pm, an X – ray reflection was observed at an angle of 230 20’. What is the corresponding interplanar spacing? [sin (23020’) = 0.396]

Solution

Correct option is

289.2 pm

 

Given that,

λ = 229 pm and θ = 23020’

substituting these value in the Bragg’s equation, we have

    

                        

                      = 289.2 pm

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