Question

1 mol of N2 H4 loses 10 mol of electrons to form a new compound X. Assuming that all the nitrogen appears in the new compound and no change in the oxidation state of hydrogen, the oxidation number in X is

Solution

Correct option is

 

With the loss of 10mol of electrons, the increase in O.N. of 2 N-atoms = 10. If x is the O.N. of M in the new compound, then

SIMILAR QUESTIONS

Q1

When phosphorous reacts with caustic soda, the products are PH3 and NaH2PO2. This reaction is an example of

Q2

When SO2 is passed into an acidified potassium dichromatic solution, the oxidation numbers of sulphur and chromium in the final products respectively are

Q3

In the standardisation of Na2S2O3 using K2Cr2O7 by iodometry, the equivalent mass of K2Cr2O7 is

Q4

Which of the following not a reducing agent?

Q5

Amongst the following which can act an oxidizing as well as reducing agent?

Q6

 

How many moles of oxalic acid are oxidised  by one mole of

KMnO4 in acid medium?

Q7

Phosphorous has the oxidation state of +1 in

Q8

The oxidation number of S in 

Q9

Oxidation number of chlorine atom in CaOCl2 are

Q10

Which of the following is the strongest reducing agent?