0.01 Mole Of Fe3O4 is Treated With Excess Of KI Solution In Presence Of Dilute H2SO4 whereby Iron Is Reduced To Fe2+ along With Liberation Of Iodine. What Volume Of 0.1 M Na2S2O3 will Be Needed To Reduce The Librated Iodine?

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Question

0.01 mole of Fe3O4 is treated with excess of KI solution in presence of dilute H2SO4 whereby iron is reduced to Fe2+ along with liberation of iodine. What volume of 0.1 M Na2S2O3 will be needed to reduce the librated iodine?

Solution

Correct option is

200 ml

 

  

n’ factor of Na2S2O3 = 2[2.5 – 2 ] = 1

Equiv. of Fe3O4 = 2 × 0.01 = Equiv . of Na2S2 O3

SIMILAR QUESTIONS

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Q10

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