﻿ 0.5 g of an impure sample of oxalate was dissolved in water and the solution made to 100 ml. On titration 10 ml of this solution required 15 ml of N/20 KMnO4 solution. Calculate the percentage of pure oxalate in the sample. : Kaysons Education

# 0.5 G Of An Impure Sample Of Oxalate Was Dissolved In Water And The Solution Made To 100 Ml. On Titration 10 Ml Of This Solution Required 15 Ml Of N/20 KMnO4 solution. Calculate The Percentage Of Pure Oxalate In The Sample.

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## Question

### Solution

Correct option is

66

The reduction half reaction is

Oxalate ion

Let N1 be the normality of the oxalate solution.

Applying normality equation, we have,

Strength of oxalate solution = Normality × Eq. wt

∴ Amount of pure  present in 100 ml

But amount of  present in impure sample = 0.5 g (Given)

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