If x2 + px + 1 Is A Factor Of ax2 + bx + c, Then

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Question

If x2 + px + 1 is a factor of ax2 + bx + c, then

Solution

Correct option is

a2 – c2 =  ab

           x2 + px + 1 is a factor of given cubic

∴    ax2 + bx + c = (x2 + px + 1) (ax + c)

The other factor is of first degree whose coefficients are chosen keeping in view the coefficient of x3 and constant term in cubic.

Comparing the coefficient of x2 and x.

    ap + c = 0     ∴   p = – c/a

 

a2 – c2 = ab

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