﻿ If p and q are distinct primes and x2 – px + q = 0 has distinct positive roots, then p + q equals : Kaysons Education

# If p and q are Distinct Primes And x2 – px + q = 0 Has Distinct Positive Roots, Then p + q equals

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## Question

### Solution

Correct option is

5

Let α and β be two roots of x2 – px + q = 0 and assume α < β. we have α + β = p, αβ = q

As q is prime, we must have α = 1, β = q.

Thus, p = 1 + q ⇒ p – q = 1.

As p and q are prime, this is possible if p = 3, q = 2.

#### SIMILAR QUESTIONS

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Q2

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