Question

If two vertices of a triangle are (3, –5) and (–7, 8) and centroid lies at the pint (–1, 1), third vertex of the triangle is at the point (a, b) then

Solution

Correct option is

2a + b = 2

SIMILAR QUESTIONS

Q1

Find the locus of a point which moves such that its distance from the point (0, 0) is twice its distance from the – axis.

Q2

Find the equation of the curve 2x2 + y2 – 3+ 5– 8 = 0 when the origin is transferred to the point (–1, 2) without changing the direction of axes.

Q3

Given the equation  through what angle should the axes be rotated so that the term in xy be waiting from the transformed equation. 

Q4

Find the locus of the point of intersection of the lines and  where α is variable.

Q5

Find the locus of a point whose co – ordinate are given by t2= 2+ 1, where is variable.

Q6

The points (a, b + c), (b, c + a) and (c, a + b) are

Q7

O(0, 0), P(–2, –2) and Q(1, –2) are the vertices of a triangle, R is a point on PQ such that PR : RQ 

Q8

If three vertices of a rectangular are (0, 0), (a, 0) and (0, b), length of each diagonal is 5 and the perimeter 14, then the area of the rectangle is

Q9

If the line joining the points A(a2, 1) and B(b2, 1) is divides in the ratio b : a at the pint P whose x-coordinate is 7, their

Q10

α is root of the equation x2 – 5x + 6 = 0 and β is a root of the equation x2– x – 30 = 0, then coordinates  of the point P farthest from the origin are