Question

Area of the triangle with vertices A(3, 7), B(–5, 2) and C(2, 5) is denoted by Δ. If ΔA, ΔBΔC denote the areas of the triangle with vertices OBC, AOC and ABO respectively, O being the origin, then

Solution

Correct option is

ΔA + ΔB = ΔC – Δ

.

SIMILAR QUESTIONS

Q1

The points (a, b + c), (b, c + a) and (c, a + b) are

Q2

O(0, 0), P(–2, –2) and Q(1, –2) are the vertices of a triangle, R is a point on PQ such that PR : RQ 

Q3

If three vertices of a rectangular are (0, 0), (a, 0) and (0, b), length of each diagonal is 5 and the perimeter 14, then the area of the rectangle is

Q4

If the line joining the points A(a2, 1) and B(b2, 1) is divides in the ratio b : a at the pint P whose x-coordinate is 7, their

Q5

If two vertices of a triangle are (3, –5) and (–7, 8) and centroid lies at the pint (–1, 1), third vertex of the triangle is at the point (a, b) then

Q6

α is root of the equation x2 – 5x + 6 = 0 and β is a root of the equation x2– x – 30 = 0, then coordinates  of the point P farthest from the origin are

Q7

 are two points whose mid-point is at the origin.  is a point on the plane whose distance from the origin is

Q8

Locus of the point P(2t2 + 2, 4t + 3), where t is a variable is

Q9

If the coordinates of An are (n, n2) and the ordinate of the center of mean position of the points A1A2, … An is 46, then n is equal to

Q10

If the axes are turned through 450. Find the transformed from the equation

                          3x2 + 3y2 + 2xy = 2