Determiner As To What Point The Axes Of The Coordinates Be Shifted So As To Remove The First Degree Terms From The Equation            f (x, Y) = 2x2 + 3y2 – 12x + 12y + 24 = 0

The value of p for which  is obtuse and  is a right angle is

A(p, 0), B(4, 0), C(5, 6) and D(1, 4) are the vertices of a quadrilateral ABCD 

If two sides of the quadrilateral are equal; area of the quadrilateral is

O (0, 0), A(1, 1), B(0, 3) are the vertices of a triangle OAB.P divides OB in the ratio 1 : 2, Q is the mid-point of AP, R divides AB in the ratio 2 : 1

1:- If 

O (0, 0), A(1, 1), B(0, 3) are the vertices of a triangle OAB.P divides OB in the ratio 1 : 2, Q is the mid-point of AP, R divides AB in the ratio 2 : 1

area of ΔPQR : area of ΔOAB is

O (0, 0), A(1, 1), B(0, 3) are the vertices of a triangle OAB.P divides OB in the ratio 1 : 2, Q is the mid-point of AP, R divides AB in the ratio 2 : 1

If S is the mid-point of PR, then QS is equal to

a and b real numbers between 0 and 1 A(a, 1), B(1, b) andC(0, 0) are the vertices of triangle

1:- If the triangle ABC is equilateral, its area is equal to

If the triangle ABC in  isosceles with AC = BC and 5(AB)² = 2(AC)² then

The origin is shifted to(1, –2)then what are the coordinates be shifted if the point (3, –5) in the new position?

If the origin is shifted to (1, –2), the coordinates of A become (2, 3). What are the original coordinates of A?

What will be the coordinates of the point  when the axes are rotated through an angle of 30⁰ in clockwise sense?