If A Vertex Of A Triangle Is (1, 1) And The Mid-point Of Two Sides Through The Vertex Are (–1, 2) And (3, 2), Then The Centroid Of The Triangle Is

Why Kaysons ?

Video lectures

Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation.

Online Support

Practice over 30000+ questions starting from basic level to JEE advance level.

Live Doubt Clearing Session

Ask your doubts live everyday Join our live doubt clearing session conducted by our experts.

National Mock Tests

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

Organized Learning

Proper planning to complete syllabus is the key to get a decent rank in JEE.

Test Series/Daily assignments

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.



If a vertex of a triangle is (1, 1) and the mid-point of two sides through the vertex are (–1, 2) and (3, 2), then the centroid of the triangle is


Correct option is

E and F are mid-point of AC and AB respectively which pass through vertex A. Hence by mid-point formula the points C and are (5, 3) and (–3, 3) respectively. Hence centroid of ΔABC by





(0, 0), A(1, 1), B(0, 3) are the vertices of a triangle OAB.divides OB in the ratio 1 : 2, Q is the mid-point of AP, R divides AB in the ratio 2 : 1

If S is the mid-point of PR, then QS is equal to


a and b real numbers between 0 and 1 A(a, 1), B(1, b) andC(0, 0) are the vertices of triangle

1:- If the triangle ABC is equilateral, its area is equal to


If the triangle ABC in  isosceles with AC = BC and 5(AB)2 = 2(AC)2 then


The origin is shifted to(1, –2)then what are the coordinates be shifted if the point (3, –5) in the new position?


If the origin is shifted to (1, –2), the coordinates of A become (2, 3). What are the original coordinates of A?


Determiner as to what point the axes of the coordinates be shifted so as to remove the first degree terms from the equation

           (x, y) = 2x2 + 3y2 – 12x + 12+ 24 = 0


What will be the coordinates of the point  when the axes are rotated through an angle of 300 in clockwise sense?


What will be the coordinates of the point in original position ifr its coordinates after rotation of axes through an angle 600  ?


The in centre of the triangle with vertices , (0, 0) and (2, 0) is


If the equation of the locus of a point equidistant from the points

(a1b1) and (a2b2) is (a1 – a1)x + (b1  –  b2)y + c = 0,

Then the value of c is :