﻿ Area of the parallelogram formed by the lines y = mx, y = mx + 1, y = nxand y = nx + 1 equals. : Kaysons Education

# Area Of The Parallelogram Formed By The Lines y = Mx, Y = Mx + 1, y = Nxand y = Nx + 1 Equals.

#### Video lectures

Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation.

#### Online Support

Practice over 30000+ questions starting from basic level to JEE advance level.

#### National Mock Tests

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

#### Organized Learning

Proper planning to complete syllabus is the key to get a decent rank in JEE.

#### Test Series/Daily assignments

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

## Question

### Solution

Correct option is

Area

mx – – 0 = 0  and nx – y – 0 = 0

mx – + 1 = 0  and nx – y + 1 = 0

#### SIMILAR QUESTIONS

Q1

If a, b, c are all unequal and different from one and the points  are collinear then ab + bc + ca =

Q2

Consider three points

,

and

, then

Q3

The lines p(p2 + 1)x – y + q = 0 and (p2 + 1)2 x + (p2 + 1)y + 2q = 0 are perpendicular to a common line for

Q4

The number of integral values of m, for which the x-coordinates of the point of intersection of the lines 2x + 4y = 9 and

y = mx + 1 is also an integral is

Q5

Let PS be the median of the triangle with vertices P(2, 2), Q(6, –1) andR(7, 3). The equation of the line passing through

(1, –1) and parallel toPS is

Q6

Let PQR be a right angled isosceles triangle, right angled at P(2, 1). If the equation of the line QR is 2x + y = 3, then the equation representing the pair of lines PQ and PR is

Q7

The point (2, 1) is shifted through a distance  units measured parallel to the line x + y = 1 in the direction of decreasing ordinates to reach Q.The image of Q w.r.t. given line is

Q8

Given the family of lines a(2x + y + 4) + b(x – 2y – 3) = 0. The number of lines belonging to the family at a distance  from any point (2, –3) is

Q9

Given four lines with equations x + 2y – 3 = 0, 3x + 4y – 7 = 0,

2x + 3y – 4 = 0, 4x + 5y – 6 = 0, then

Q10

The area bounded by the curves