## Question

### Solution

Correct option is

2

The given are x2 – (y – 1)2 = 0

or x – y + 1 = 0, x + y – 1 = 0

Their bisector are x = 0, y = 1 and x + y = 3

Solving in pairs the vertices of ΔABC are (0, 1), (0, 3) and (2, 1). One side along y-axis. .

#### SIMILAR QUESTIONS

Q1

The area bounded by the curves Q2

A line making an angle with the + ive direction of x-axis passes throughP(5, 6) to meet the line x = 6 at Q and y = 9 at R the QR is

Q3

A straight line through the origin O meets the parallel lines 4x + 2y = 9 and 2x + y + 6 = 0 at points P and Q respectively. Then the point Odivides the segment PQ in the ratio

Q4

Orthocenter of triangle whose vertices are (0, 0), (3, 4), (4, 0) is

Q5

The three lines 4x – 7y + 10 = 0, x + y = 5 and 7x + 4y = 15 from the sides of a triangle. The line (1, 2) is its

Q6

The equation to the side of a triangle are x – 3y = 0, 4x + 3= 5 and 3x + y = 0. The line 3x – 4y = 0 passes through

Q7

One vertex of the equilateral triangle with centroid at the origin and one side as x + y – 2 = 0 is

Q8

A point equidistant from the lines 4x + 3y + 10 = 0, 5x – 12y + 26 = 0 and 7x + 24y – 50 = 0 is

Q9

Let P = (–1, 0), Q = (0, 0) and be three points. Then the equation of the bisector of the angle PQR is

Q10

The equation of the straight line which passes through the point (1, –2) and cuts off equal intercepts from the axes will be