The Straight Line Passing Through The Point Of Intersection Of The Straight Lines x – 3y + 1 = 0 And 2x + 5y – 9 = 0 and Having Infinite Slope And At A Distance 2 Unit From The Origin Has The Equation

The equation to the side of a triangle are x – 3y = 0, 4x + 3y = 5 and 3x + y = 0. The line 3x – 4y = 0 passes through 

One vertex of the equilateral triangle with centroid at the origin and one side as x + y – 2 = 0 is

A point equidistant from the lines 4x + 3y + 10 = 0, 5x – 12y + 26 = 0 and 7x + 24y – 50 = 0 is

Let P = (–1, 0), Q = (0, 0) and  be three points. Then the equation of the bisector of the angle PQR is

Area of Δ formed by line x + y = 3 and  bisectors of pair of straight lines x² – y² +2y = 1is

The equation of the straight line which passes through the point (1, –2) and cuts off equal intercepts from the axes will be

The three lines 3x + 4y + 6 = 0,  and 4x + 7y + 8 = 0 are

The line (p + 2q)x + (p – 3q)y = p – q for different values of p and qpasses through the point

The locus of the mid-point of te portion intercepted between the axes by the line  where p is constant is

shifting of origin (0, 0) to (h, k)

                  Rotation of axes through an angle θ.

1:- by rotating the axes through an angle θ the equation xy – y² – 3y + 4 = 0 is transformed to the from which does not contain the term of xy then  ….