Shifting Of Origin (0, 0) To (h, K)                                            Rotation Of Axes Through An Angle θ.                            1:- By Rotating The Axes Through An Angle θ The Equation xy – Y2 – 3y + 4 = 0 is Transformed To The From Which Does Not Contain The Term Of xy then  ….

One vertex of the equilateral triangle with centroid at the origin and one side as x + y – 2 = 0 is

A point equidistant from the lines 4x + 3y + 10 = 0, 5x – 12y + 26 = 0 and 7x + 24y – 50 = 0 is

Let P = (–1, 0), Q = (0, 0) and  be three points. Then the equation of the bisector of the angle PQR is

Area of Δ formed by line x + y = 3 and  bisectors of pair of straight lines x² – y² +2y = 1is

The equation of the straight line which passes through the point (1, –2) and cuts off equal intercepts from the axes will be

The three lines 3x + 4y + 6 = 0,  and 4x + 7y + 8 = 0 are

The line (p + 2q)x + (p – 3q)y = p – q for different values of p and qpasses through the point

The locus of the mid-point of te portion intercepted between the axes by the line  where p is constant is

The straight line passing through the point of intersection of the straight lines x – 3y + 1 = 0 and 2x + 5y – 9 = 0 and having infinite slope and at a distance 2 unit from the origin has the equation

Axes are rotating through a +ive obtuse angle θ so that the transformed equation of the curve 3x² – 6xy + 3y² + 7x – 3 = 0 is free from the term of xy then the coefficient of x² in the transformed equation is…