Equation Of The Circle Which Passes Through The Origin, Has Its Centre On The Line x + y = 4 And Cuts The Circle X2 + y2 – 4x + 2y + 4 = 0 Orthogonally, Is

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Question

Equation of the circle which passes through the origin, has its centre on the line x + y = 4 and cuts the circle

x2 + y2 – 4x + 2y + 4 = 0 orthogonally, is

Solution

Correct option is

None of these.

Since the centre of the required circle lies on x + y = 4, let (g, 4 – g) be this centre. Since the circle passes through the origin, let its equation be

           x2 + y2 – 2gx – 2(4 – g)y = 0  

As this circle  cuts the given circle orthogonally, we have

            

So that equation of the required circle is x2 + y2 – 4x – 4y = 0.

SIMILAR QUESTIONS

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Q2

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Q4

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Q5

 

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Q6

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Q7

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Q8

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Q9

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Q10

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