﻿ Equation of a circle through the origin and belonging to the co-axial system, of which the limiting points are (1, 2), (4, 3) is : Kaysons Education

# Equation Of A Circle Through The Origin And Belonging To The Co-axial System, Of Which The Limiting Points Are (1, 2), (4, 3) Is

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## Question

### Solution

Correct option is

2x2 + 2y2 – x – 7y = 0

Since the limiting points of a system of co-axial circles are the point circles (radius being zero), two members of the system are

and (x-4)2 + (y-3)2 = 0

x2 + y2 - 8x -6y +25 = 0

The co-axial system of circles with these as members is

It passes through the origin if 5 + 25λ = 0

or                                              λ = –(1/5),

which gives the equation of the required circle as

#### SIMILAR QUESTIONS

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