Question

A square is inscribed in the circle x2 + y2 – 2x + 4y + 3 = 0. Its sides are parallel to the co-ordinates axes. Then one vertex of the square is

Solution

Correct option is

None of these

The centre of the given circle is (1, –2). Since the sides of the square inscribed in the circle are parallel to the coordinates axes, so the coordinates of any vertex cannot be equal to 1 and its y coordinate cannot be equal to –2. 

Hence none of the point given in (a), (b) or (c) can be the vertex of the square. Thus the correct answer is none of these.

SIMILAR QUESTIONS

Q1

The coordinates of the point on the circle x2 + y2 – 2x – 4y – 11 = 0 farthest from the origin are 

Q2

A circle passes through the origin O and cuts the axis at A(a, 0) and B(0,b). The reflection of O in the line AB is the point

Q3

The length of the longest ray drawn from the point (4, 3) to the circle x2y2 + 16x + 18y + 1 = 0 is equal to

Q4

1:- The chords in which the circle C cuts the members of the family S of circles through A and B are con-current at  

Q5

2:- Equations of the member of the family S which bisects the circumference of C is

Q6

3:- If O is the origin and P is the centre of C, then the difference of the squares of the lengths of the tangents from A and B to the circle is equal to

Q7

If the two (x – 1)2 + (y – 3)2 = r2 and x2 + y2 – 8x + 2y + 8 = 0 intersect in two distinct points, then

Q8

The distance between the chords of contact of the tangent to the circle x2 + y2 + 2gx + 2fy + c = 0 from the origin and the point (gf) is

Q9

The angle between the tangents drawn from the origin to the circle (x – 7)2 + (y + 1)2 = 25 is

Q10

If the lines 3x – 4y – 7 = 0 and 2x – 3y – 5 = 0 are two diameters of a circle of area 49π square units, then the equation of the circle is: