﻿ If the lines 3x – 4y – 7 = 0 and 2x – 3y – 5 = 0 are two diameters of a circle of area 49π square units, then the equation of the circle is: : Kaysons Education

# If The Lines 3x – 4y – 7 = 0 And 2x – 3y – 5 = 0 Are Two Diameters Of A Circle Of Area 49π Square Units, Then The Equation Of The Circle Is:

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## Question

### Solution

Correct option is

x2 + y2 – 2x + 2y – 47 = 0

Centre is (1, –1) the point of intersection of diameters. Area ⇒

r = 7. Hence its equation is (x – 1)2 + (y + 1)2 = 49.

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