The Equation Of The Locus Of The Mid Points Of The Chords Of The Circle 4x2 + 4y2 – 12x + 4y + 1 = 0 That Subtend An Angle Of  at Its Centre Is:

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Question

The equation of the locus of the mid points of the chords of the circle 4x2 + 4y2 – 12x + 4y + 1 = 0 that subtend an angle of  at its centre is:

Solution

Correct option is

Equation of the given circle is

                   4x2 + 4y2 – 12x + 4y + 1 = 0

 or                 x2 + y2 – 3x + y +  = 0                         …(1)   

Comparing (1) with

                   x2 + y2 + 2gx + 2fy + c = 0  

              

            

              

Centre of the circle is    

Radius of the circle is    

                                        

If m (hk) is the middle point of the chord AB which subtend 120o at the centre C then

                                                                                 

                           

                        

                 

  

                       

                       

                      

                       

                      

So the locus of the point (hk) is  

                    

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