﻿ The equation of the locus of the mid points of the chords of the circle 4x2 + 4y2 – 12x + 4y + 1 = 0 that subtend an angle of  at its centre is: : Kaysons Education

# The Equation Of The Locus Of The Mid Points Of The Chords Of The Circle 4x2 + 4y2 – 12x + 4y + 1 = 0 That Subtend An Angle Of  at Its Centre Is:

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## Question

### Solution

Correct option is

Equation of the given circle is

4x2 + 4y2 – 12x + 4y + 1 = 0

or                 x2 + y2 – 3x + y +  = 0                         …(1)

Comparing (1) with

x2 + y2 + 2gx + 2fy + c = 0

Centre of the circle is

If m (hk) is the middle point of the chord AB which subtend 120o at the centre C then

So the locus of the point (hk) is

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