The Normal 3x – 4y = 4 And 6x – 8y – 7 = 0 Are Tangents To The Circle. Then Its Radius Is:

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Question

The normal 3x – 4y = 4 and 6x – 8y – 7 = 0 are tangents to the circle. Then its radius is:

Solution

Correct option is

3/4

Equation of the given lines are

          3x – 4y – 4 = 0                               …(1) 

           

Slope of line (1) is = 3/4 

Slope of line (2) is = 3/4  

So lines (1) & (2) are parallel 

∵ the diameter of the circle is the perpendicular distance b, t the parallel lines. If p1 & p2 are the perpendicular distance from (0, 0) on line (1) & (2) then  

   

   

Length of the diameter

  

                      

                   

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Q10

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