﻿ Find the equation of the chord of x2 + y2 – 6x + 10y – 9 = 0 which is bisected at (–2, 4).  : Kaysons Education

# Find The Equation Of The Chord Of x2 + y2 – 6x + 10y – 9 = 0 Which Is Bisected At (–2, 4).

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## Question

### Solution

Correct option is

Equation of the given circle is

x2 + y2 – 6x + 10y – 9 = 0                       …(1)

Equation of the chord of the circle (1) bisected at the point (–2, 4) is given by-

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