Question

Solution

Correct option is Center (2, –3), S(3, –3) vertex is A(4, –3).

From the diagram ae = 1, CA = 4 – 2 = 2. = 2 or ae = 1 So equation of ellipse is .

SIMILAR QUESTIONS

Q1

The locus of the poles of the tangents to the ellipse w.r.t. the circle x2 + y2 = a2 is

Q2

A variable point P on the ellipse eccentricity e is joined to its foci S, S’. The locus of the incentre of is an ellipse of eccentricity

Q3

The locus of the point of intersection of two perpendicular tangent to the ellipse , is

Q4

The equation of the ellipse with focus (–1, 1), directrix x – y + 3 = 0 and eccentricity , is

Q5

The equation of the ellipse whose center is at origin and whihch passes through the points (–3, 1) and (2, –2) is

Q6

The equation x2 + 4xy + y2 + 2x + 4y + 2 = 0 represents

Q7

The equation of the tangent to the ellipse x2 + 16y2 = 16 making an angle of 600 with x-axis is

Q8

The equation of the ellipse whose foci are and one of its directrix is 5x = 36.

Q9

Center of hyperbola 9x2 – 16y2 + 18x + 32y – 151 = 0 is

Q10

Find the eccentricity of the ellipse, whose foci are (–3, 4) and (3, –4) and which passes through the point (1, 2)