Question
The equation of the ellipse whose centre is (2, –3), one of the foci is (3, –3) and the responding vertex is (4, –3) is

None of these



easy
Solution
Center (2, –3), S(3, –3) vertex is A(4, –3).
From the diagram
ae = 1, CA = 4 – 2 = 2.
a = 2 or ae = 1
So equation of ellipse is
.
SIMILAR QUESTIONS
The locus of the poles of the tangents to the ellipse w.r.t. the circle x^{2} + y^{2} = a^{2} is
A variable point P on the ellipse eccentricity e is joined to its foci S, S’. The locus of the incentre of is an ellipse of eccentricity
The locus of the point of intersection of two perpendicular tangent to the ellipse , is
The equation of the ellipse with focus (–1, 1), directrix x – y + 3 = 0 and eccentricity , is
The equation of the ellipse whose center is at origin and whihch passes through the points (–3, 1) and (2, –2) is
The equation x^{2} + 4xy + y^{2} + 2x + 4y + 2 = 0 represents
The equation of the tangent to the ellipse x^{2} + 16y^{2} = 16 making an angle of 60^{0} with xaxis is
The equation of the ellipse whose foci are and one of its directrix is 5x = 36.
Center of hyperbola 9x^{2} – 16y^{2} + 18x + 32y – 151 = 0 is
Find the eccentricity of the ellipse, whose foci are (–3, 4) and (3, –4) and which passes through the point (1, 2)