﻿ The equation of the conic with focus at (1, –1), directrix along x – y + 1 = 0 and with eccentricity  is : Kaysons Education

# The Equation Of The Conic With Focus At (1, –1), Directrix Along x – y + 1 = 0 And With Eccentricity  is

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## Question

### Solution

Correct option is

2xy – 4x + 4y + 1 = 0

S(1, –1) = focus, directrix is (x – y + 1) = 0                   …… (1)

P(x, y) is any point on the curve and

Curve is hyperbola

PS = ePM

Length of ⊥ from P on (x – y + 1) = 0

Solve to get –4x + 4y + 2yx + 1 = 0

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