The Eccentricity Of The Conjugate Hyperbola Of The Hyperbola x2 – 3y2 = 1 Is

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Question

The eccentricity of the conjugate hyperbola of the hyperbola x2 – 3y2 = 1 is

Solution

Correct option is

2

 

x2 – 3y2 = 1 

If e1 is eccentricity of conjugate hyperbola a

⇒ e1 = 2

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