﻿   A mass m =50g is dropped on a vertical spring of spring constant 500 N/m from a height h  =10 cm as shown in figure. The mass sticks to the spring and executed simple harmonic oscillations after that. A concave mirror of focal length 12 cm facing the mass is fixed with its principal axis coinciding with the line of motion of  the mass, its pole being at a distance of 30 cm from the free end of the spring. Find the length in which the image of the mass oscillated                                                                                                     : Kaysons Education

# A Mass M =50g Is Dropped On A Vertical Spring Of Spring Constant 500 N/m From A Height H  =10 Cm As Shown In Figure. The Mass Sticks To The Spring And Executed Simple Harmonic Oscillations After That. A Concave Mirror Of Focal Length 12 Cm Facing The Mass Is Fixed With Its Principal Axis Coinciding With The Line Of Motion Of  the Mass, Its Pole Being At A Distance Of 30 Cm From The Free End Of The Spring. Find The Length In Which The Image Of The Mass Oscillated

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## Question

### Solution

Correct option is

1.24 cm

mg = kx

Now mean position at 30 + 0.1 = 30.1 cm from mirror

Mg (n + y) = 1/2 ky2

u1 = – 31.5 cm,        – (31.5 – 30.1) =  – 1.4 cm

f = – 12 cm            f = – 12 cm, u2 = 30.1 – 1.4 = – 28.7 cm

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