## Question

### Solution

Correct option is

0.176 nm

CsCl has a bcc lattice. So, dbody = Or    dbody = 0.4123 nm = 0.7141 nm

The sum of the ionic radii of Cs+ and Cl- ions is half this distance ie = 0.3572 nm

Ionic radius of Cs+ = 0.3571 – 0.181 = 0.1761

#### SIMILAR QUESTIONS

Q1

The number of atoms/molecules contained in one face centred cubic unit cell of a monoatomic substance is

Q2

In a face centred cubic cell, an atom at the face contributes to the unit cell

Q3

A fcc unit cell of aluminum contains the equivalent of how many atoms?

Q4

In octahedral holes (voids)

Q5

The number of octahedral sites per sphere in a fcc structure is

Q6

The interionic distance for cesium chloride crystal will be

Q7

For cubic coordination, the value of radius ratio is

Q8

The ratio of cationic radius of anionic radius in an ionic crystal is greater than 0.732. its coordination number is

Q9

The vacant space in the bcc unit cell is

Q10

If the value of ionic radius ratio is 0.52 in an ionic compound, the geometrical arrangement of ions in crystal is