﻿ Calculate the ionic radius of a Cs+ ion, assuming that the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a Cl- ion 0.181 nm. : Kaysons Education

# Calculate The Ionic Radius Of A Cs+ ion, Assuming That The Cell Edge Length For CsCl Is 0.4123 Nm And That The Ionic Radius Of A Cl- ion 0.181 Nm.

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## Question

### Solution

Correct option is

0.176 nm

CsCl has a bcc lattice. So, dbody =

Or    dbody =  0.4123 nm = 0.7141 nm

The sum of the ionic radii of Cs+ and Cl- ions is half this distance ie

= 0.3572 nm

Ionic radius of Cs+ = 0.3571 – 0.181 = 0.1761

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