The equation ex + 1 + x – 2 = 0 as
The function f satisfying
Suppose f is differentiable on R and a ≤ f’(x) ≤ b for all x ∈ R where a, b> 0. If f (0) = 0, then
, for every real number, then minimum value of f
The coordinates of the point on the parabola y2 = 8x which is at minimum distance from the circle x2 + (y + 6)2 = 1 are
The image of the interval [- 1, 3] under the maping
f (x) = 4x2 – 12x is.
The difference between the greatest and least values of the function