Why Kaysons ?

Video lectures

Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation.

Online Support

Practice over 30000+ questions starting from basic level to JEE advance level.

Live Doubt Clearing Session

Ask your doubts live everyday Join our live doubt clearing session conducted by our experts.

National Mock Tests

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

Organized Learning

Proper planning to complete syllabus is the key to get a decent rank in JEE.

Test Series/Daily assignments

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

SPEAK TO COUNSELLOR ? CLICK HERE

Question

 

 

Solution

Correct option is

π/4 – α

   

and tan (α + 2β

                

Since 0 < β < π/2 and tan 2β = 3/4 > 0, we get 0 < 2β < π/2. Also,

0 < α < π/2. Hence, 0 < α + 2β < π and tan (α + 2β) = 1, so that

α + 2β = π/4 ⇒ 2β = π/4 – α.

SIMILAR QUESTIONS

Q1

  is equal to

Q2

An angle α is divided into two parts so that the ratio of the tangents of these parts is λ. If the difference between these parts is x then sinx/sinα is equal to

Q3

 

 or equal to

Q4

Given θ Ïµ (0,π/4) and t1 = (tan θ)tanθ t2 = (tan θ)cotθt3 = (cot θ)tanθand t4 = (cot θ)cotθ then

Q5

If x = sin αy = sin βz = sin (α + β) then cos (α + β) =

Q6

The radius of the circle

 

Q7

If tan x + tan (x + π/3) + tan (x + 2π/3) = 3, then

Q8

The equation cos 2x + a sin x = 2a – 7 possesses a solution if

Q9

sin 470 + sin 610 – sin 110 – sin 250 is equal to

Q10

If 3π/4 < α < π, then  is equal to