## Question

### Solution

Correct option is

6

The first equation can be written as        When x + y = 0, we have to reject x + y = 1 or –1 and solve it with x – y = 1 or x – y = –1 which give (1/2, –1/2) or (–1/2, 1/2) as the possible solutions. Again solving with x = 0 we get and solving with y = 0 we get as the other solutions. Thus we have six sets of solutions for x and y.

#### SIMILAR QUESTIONS

Q1

The number of values of x in the interval satisfy the equation is

Q2 Q3

The number of solutions of the pair of equations  in the interval is

Q4

If are the smallest +ive angles in ascending order of magnitude which have their sines equal to a +ive quantity then the value of Q5

The equation possesses a solution if

Q6

The number of values of x in the interval satisfying the equation is

Q7

The number of solutions of the equation Q8

If n be the number of solutions of the equation , then n =

Q9

The values of x between 0 and which satisfy the equation are in A.P. The common difference of the A.P.

Q10  