Question

 

For what value of k the points (k, 2 – 2k), (–k + 1, 2k) and (–4 – k, 6 – 2k) are collinear?

Solution

Correct option is

–1

 

Let A ≡ (k, 2 – 2k), B ≡ (–k + 1, 2k) and C ≡ (–4 – k, 6 – 2k) are collinear then 

        Slope of AB = Slope of AC

  

  

  

  

  

.

SIMILAR QUESTIONS

Q1

Find the inclination on the line whose slope is .

Q2

Find the slope of the line through the points (4, –6), (–2, –5).

Q3

Determine λ, so that 2 is the slope of the line through (2, 5) and (λ, 3).

Q4

 

Find whether the points (–a, –b), [–(+ 1)a, –(s + 1)b] and [(t – 1)a, (t – 1)b] are collinear?

Q5

Find the angle between the lines joining the points (0, 0), (2, 3) and (2, –2), (3, 5).

Q6

The angle between two lines is  and the slope of one of them is . Find the slope of the other line.

Q7

 

A line passes through the points A(2, –3) and B(6, 3). Find the slopes of the lines which are  

1. parallel to AB

2. perpendicular to AB

Q8

 

Find the equation of the straight line parallel to y-axis and at a distance  

(i).3 units to the right

(ii). 2 units to the left

Q9

 

Find the equation of the straight line parallel to x-axis and at a distance

(i). 5 units above the x-axis

(ii). 9 units below the x-axis

Q10

 

Find the equation of the straight line which passes through the point (2, –3) and is  

1. parallel to the x-axis

2. perpendicular to the x-axis