﻿   A solution of ‘X’ containing 0.02 mole of ‘X’ per litre is mixed with another solution, a solution of ‘Y’ containing 0.02 mole of ‘Y’ per litre.       1 L of mixture solution + AgBO3 → ‘A’ ↓       1 L of mixture solution + Excess BaCl2 → ‘B’↓   If  ‘X’ is [Co(NH3)5SO4]Br, and          ‘Y’ is [Co(NH3)5Br]SO4, then the number of moles of ‘A’ and ‘B’ obtained are, respectively : Kaysons Education

# A Solution Of ‘X’ Containing 0.02 Mole Of ‘X’ Per Litre Is Mixed With Another Solution, A Solution Of ‘Y’ Containing 0.02 Mole Of ‘Y’ Per Litre.       1 L Of Mixture Solution + AgBO3 → ‘A’ ↓       1 L Of Mixture Solution + Excess BaCl2 → ‘B’↓   If  ‘X’ Is [Co(NH3)5SO4]Br, And          ‘Y’ Is [Co(NH3)5Br]SO4, Then The Number Of Moles Of ‘A’ And ‘B’ Obtained Are, Respectively

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## Question

### Solution

Correct option is

0.01, 0.01

The total volume of mixture solution = 2L(1L + 1L = 2L) moles of ‘X’ i.e., [Co(NH3)5SO4]Br is 0.2 moles i.e., it is 0.01 mole/L

Similarly moles of ‘Y’ i.e., [Co(NH3)5Br] is also 0.01 mole/L.

1 L of solution

0.01 mole

1 litre of solution : 0.01 mole.

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