A Solution Of ‘X’ Containing 0.02 Mole Of ‘X’ Per Litre Is Mixed With Another Solution, A Solution Of ‘Y’ Containing 0.02 Mole Of ‘Y’ Per Litre.       1 L Of Mixture Solution + AgBO3 → ‘A’ ↓       1 L Of Mixture Solution + Excess BaCl2 → ‘B’↓   If  ‘X’ Is [Co(NH3)5SO4]Br, And          ‘Y’ Is [Co(NH3)5Br]SO4, Then The Number Of Moles Of ‘A’ And ‘B’ Obtained Are, Respectively

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Question

 

A solution of ‘X’ containing 0.02 mole of ‘X’ per litre is mixed with another solution, a solution of ‘Y’ containing 0.02 mole of ‘Y’ per litre. 

     1 L of mixture solution + AgBO3 → ‘A’ ↓ 

     1 L of mixture solution + Excess BaCl2 → ‘B’↓  

If  ‘X’ is [Co(NH3)5SO4]Br, and    

     ‘Y’ is [Co(NH3)5Br]SO4,

then the number of moles of ‘A’ and ‘B’ obtained are, respectively

Solution

Correct option is

0.01, 0.01

 

The total volume of mixture solution = 2L(1L + 1L = 2L) moles of ‘X’ i.e., [Co(NH3)5SO4]Br is 0.2 moles i.e., it is 0.01 mole/L 

Similarly moles of ‘Y’ i.e., [Co(NH3)5Br] is also 0.01 mole/L.

                     

1 L of solution     

                                       

                                                                       0.01 mole

1 litre of solution : 0.01 mole.

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