The Number Of Ways In Which 20 Different Pearls Of Two colours can Be Set Alternately On A Necklace, There Being 10 Pearls Of Each colour is :

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Question

The number of ways in which 20 different pearls of two colours can be set alternately on a necklace, there being 10 pearls of each colour is :

Solution

Correct option is

Twenty pearls ≡ 10 pearls of one color and 10 pearls of another color

Step I : First arrange pearls of same color in 1/2 (10 – 1)!

                             = 1/2 × 9!

Step II : Now arrange pearls of another color in between the arranged 10 pearls in 10! Ways.

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