Question

Find the area of the quadrilateral with vertices (3, 3), (1, 4), (–2, 1), (2, –3).

 

Solution

Correct option is

37/2

Let the given vertices be ABCD respectively. 

 
 

 

Join AC

Area of ABCD = area of triangle ABC + area of triangle ACD

                                   

SIMILAR QUESTIONS

Q1

If two of the lines given by the equation ax3 – 9yx2 – y2x + 4y3 = 0 are perpendicular then a is equal to

Q2

The number of straight lines equidistant from three non-collinear points in the plane of the points is equal to

Q3

A line bisecting the ordinate PN of a point P(at2, 2at), t > 0 on the parabola y2 = 4ax, a > 0 is drawn parallel to the axis to meet the curve at Q. If NQ and the tangent at the point P meet at, T, then the coordinates of point T is (where point N lie on the axis)

Q4

If the pair of line  intersect on x-axis, then α is equal to –

Q5

If the area of the rhombus enclosed by the lines  be 2 square units, then

Q6

If a2 + b2 – c2 – 2ab = 0 then the point of concurrency of family of straight lines ax + by + c = 0lies on the line –

Q7

All chords of the curve 3x2 – y2 –2x + 4y = 0 that subtends a right angle at the origin, pass through a fixed point whose co-ordinate is –

Q8

In a triangle ABC,  and point A lies on line y = 2x + 3 where  Area of  is such that [∆] = 5. Possible co-ordinates of ∆ is/are –

Q9

 then the point (x, y) lies on same side of the line 2x + y – 6 = 0 as the point –

Q10

A straight line segment of length ‘p’ moves with its ends on two mutually perpendicular lines. find the locus of the point which divides the line in the ratio 1:2.